C Programming Language :: fuction to divide by three


	fuction to divide by three Without using /,% and * operators. write a function to divide a number by 3. itoa() function is available rajm2@gmail.com writes: > Without using /,% and * operators. write a function to divide a > number by 3. Do your own homework. -- Regards, Hallvard In article <1180189817.862810.237@r19g2000prf.googlegroups.com>, rajm2@gmail.com wrote: > Without using /,% and * operators. write a function to divide a > number by 3. > itoa() function is available Who needs itoa()? Assuming integer division and only positive inputs, it's trivial, although not precisely efficient, or necessarily fast, to simply do repetitive subtraction. -- Don Bruder - dak@sonic.net - If your "From:" address isn't on my whitelist, or the subject of the message doesn't contain the exact text "PopperAndShadow" somewhere, any message sent to this address will go in the garbage without my ever knowing it arrived. Sorry... <http://www.sonic.net/~dakidd> for more info In article <hbf.20070526u@bombur.uio.no>, Hallvard B Furuseth <h.b.furus@usit.uio.no> wrote: > rajm2@gmail.com writes: > > Without using /,% and * operators. write a function to divide a > > number by 3. > Do your own homework. Hey! I just had a great idea... Let's see if this one gets him dinged: int DivBy3(int x) { int q; for (q=0;x>2;x-=3,q++); return q; } (ROT-13) Bs pbhefr, guvf yvggyr "dhvpx-a-qvegl" jvyy bayl jbex sbe cbfvgvir vachgf, naq vg'f tbvat gb or (pbzcnengviryl fcrnxvat) fybjre guna gur frpbaq pbzvat sbe ovt vachgf, ohg vg'yy qb gur wbo. Naq vg fubhyq or "nqinaprq" rabhtu gung gur grnpure jvyy fync uvz sbe boivbhf purngvat vs ur npghnyyl hfrf vg - n pynff ng gur yriry guvf bar frrzf gb or onfrq ba uvf "qb zl ubzrjbex sbe zr" erdhrfgf jba'g unir gur svefg pyhr nobhg gur "snapl" gevpx bs penzzvat vg nyy vagb n sbe () ybbc (vs gurl'ir rira yrnearq nobhg gurz ng nyy lrg) naq jvgu uvf qvfcynlrq yriry bs vtabenapr, V unir ab qbhog ur'yy or hanoyr gb rira ORTVA rkcynvavat ubj vg jbexf jura gur grnpure nfxf uvz. Ubcrshyyl rafhevat ng yrnfg na S ba guvf nffvtazrag sbe purngvat. -- Don Bruder - dak@sonic.net - If your "From:" address isn't on my whitelist, or the subject of the message doesn't contain the exact text "PopperAndShadow" somewhere, any message sent to this address will go in the garbage without my ever knowing it arrived. Sorry... <http://www.sonic.net/~dakidd> for more info rajm2@gmail.com wrote: > Without using /,% and * operators. write a function to divide a > number by 3. > itoa() function is available d = 0; while ((a -= 3) > 0) d++; (I think this is such as not to be assumed the poor students work) -- <http://www.cs.auckland.ac.nz/~pgut001/pubs/vista_cost.txt> <http://www.securityfocus.com/columnists/423> <http://www.aaxnet.com/editor/edit043.html> <http://kadaitcha.cx/vista/dogsbreakfast/index.html> cbfalconer at maineline dot net -- Posted via a free Usenet account from http://www.teranews.com In article <4658774B.ED13E@yahoo.com>, CBFalconer <cbfalco@yahoo.com> wrote: > rajm2@gmail.com wrote: > > Without using /,% and * operators. write a function to divide a > > number by 3. > > itoa() function is available > d = 0; > while ((a -= 3) > 0) d++; > (I think this is such as not to be assumed the poor students work) Heh... GMTA :) -- Don Bruder - dak@sonic.net - If your "From:" address isn't on my whitelist, or the subject of the message doesn't contain the exact text "PopperAndShadow" somewhere, any message sent to this address will go in the garbage without my ever knowing it arrived. Sorry... <http://www.sonic.net/~dakidd> for more info CBFalconer said: > rajm2@gmail.com wrote: >> Without using /,% and * operators. write a function to divide a >> number by 3. >> itoa() function is available > d = 0; > while ((a -= 3) > 0) d++; > (I think this is such as not to be assumed the poor students work) Since the itoa function is available, wouldn't it be simpler to use: result_of_division_by_3 = itoa(n); Of course, this assumes that itoa divides its numeric input by 3, but that's not an unreasonable assumption, given the question text. -- Richard Heathfield "Usenet is a strange place" - dmr 29/7/1999 http://www.cpax.org.uk email: rjh at the above domain, - www. On 2007-05-26 07:30:18 -0700, rajm2@gmail.com said: > Without using /,% and * operators. write a function to divide a > number by 3. > itoa() function is available Here ya' go; enjoy: #include <stdbool.h> #include <stdio.h> #include <complex.h> int divide(int n, unsigned d) { int j,l; for(j=0;j<d;j-=(int)cpow(I,2)); { int k=0; if(n>=0) for(k=n,l=0;k>=j;k-=j,++l); else for(k=-n,l=0;k>=j;k-=j,--l); } return l; } int divide_by_3(int i) { return divide(i, 3); } int main() { int i; while(true) { printf("Enter a number (enter a non-number to quit): "); fflush(stdout); if(scanf("%d", &i) != 1) { return 0; } else { printf("%d / 3 == %d\n", i, divide_by_3(i)); } } } -- Clark S. Cox III clarkc@gmail.com On May 26, 3:30 pm, rajm2@gmail.com wrote: > Without using /,% and * operators. write a function to divide a > number by 3. > itoa() function is available double divide_by_3 (double x) { return x > 0.0 ? exp (log (x) - log (3.0)) : x < 0.0 ? -exp (log (-x) - log (3.0)) : x; - Hide quoted text - } rajm2@gmail.com wrote On 05/26/07 10:30,: > Without using /,% and * operators. write a function to divide a > number by 3. > itoa() function is available #include <stdlib.h> int divideBy3(int aNumber) { div_t d = div(aNumber, 3); return d.quot; } -- Eric.Sos@sun.com rajm2@gmail.com wrote: > Without using /,% and * operators. write a function to divide a > number by 3. > itoa() function is available Untested: int DivideByThree(int number) { char mybuf[64]; sprintf(mybuf,"exit `expr %d / 3`",number); return( system(mybuf) ); } -- +-------------------------+--------------------+-----------------------+ \| Kenneth J. Brody \| www.hvcomputer.com \| #include \| \| kenbrody/at\spamcop.net \| www.fptech.com \| <std_disclaimer.h> \| +-------------------------+--------------------+-----------------------+ Don't e-mail me at: <mailto:ThisIsASpamT@gmail.com> On May 28, 3:15 pm, "christian.bau" <christian.@cbau.wanadoo.co.uk> wrote: > On May 26, 3:30 pm, rajm2@gmail.com wrote: > > Without using /,% and * operators. write a function to divide a > > number by 3. > > itoa() function is available > double divide_by_3 (double x) { > return x > 0.0 ? exp (log (x) - log (3.0)) : > x < 0.0 ? -exp (log (-x) - log (3.0)) : x; > } I like this one. I do see a minor problem for x == 0. On May 29, 11:21 am, user923005 <dcor@connx.com> wrote: > On May 28, 3:15 pm, "christian.bau" <christian.@cbau.wanadoo.co.uk> > wrote: > > On May 26, 3:30 pm, rajm2@gmail.com wrote: > > > Without using /,% and * operators. write a function to divide a > > > number by 3. > > > itoa() function is available > > double divide_by_3 (double x) { > > return x > 0.0 ? exp (log (x) - log (3.0)) : > > x < 0.0 ? -exp (log (-x) - log (3.0)) : x; > > } > I like this one. I do see a minor problem for x == 0. As the wise baboon in "The Lion King" or Ben Pfaff might say: "Look Harder." Indeed, the matter is cared for.