Python Programming Language :: how can I get the name of a method inside it?


	how can I get the name of a method inside it? I would like to know if it's possible to retrieve the name of a method when you're inside it. For example, in the following script, I would like to assign _s so that it prints "you are in method1". ************************************* class Obj1: def __init__(self): ... def method1(self): _s = ??? print "you are in %s" % _s x = Obj1() x.method1() - Hide quoted text - > I would like to know if it's possible to retrieve the name of a method when > you're inside it. For example, in the following script, I would like to > assign _s so that it prints "you are in method1". > *********************************** > class Obj1: > def __init__(self): > ... > def method1(self): > _s = ??? > print "you are in %s" % _s > x = Obj1() > x.method1() i'm no expert on the subject, but AFAIK, there's no way to do this. why not just print "you are in method1"? what are you exactly trying to do? "Sbastien Vincent" <sebastien_nimp73<@> wrote: > I would like to know if it's possible to retrieve the name of a method when > you're inside it. For example, in the following script, I would like to > assign _s so that it prints "you are in method1". > ************************************* > class Obj1: > def __init__(self): > ... > def method1(self): > _s = ??? > print "you are in %s" % _s For debugging purposes, _s = sys._getframe(0).f_code.co_name should work (after you've done an "import sys" somewhere appropriate, of course;-). The _ in front of _getframe, as well as the klunkiness of it all, are all indications that this is _not_ recommended for "production use" -- like most of Python's introspection features, it IS chiefly meant for debugging purposes. Alex