Python Programming Language :: how to print out each single char from a string in HEX format?


	how to print out each single char from a string in HEX format? guys, I've researched python pretty much but still have no idea how to print out each single character from a string in HEX format? Hope someone can give me some hints. Thanks a lot. e.g. ###here is a string a='01234' ###how to print out it out in this way 0x31 0x31 0x32 0x33 0x34 En Mon, 04 Jun 2007 20:03:39 -0300, mike <needpass@gmail.com> escribi: > I've researched python pretty much but still have no idea how to print > out each single character from a string in HEX format? Hope someone > can give me some hints. Thanks a lot. > e.g. ###here is a string > a='01234' > ###how to print out it out in this way > 0x31 0x31 0x32 0x33 0x34 py> a='01234' py> for c in a: ... print "%#x" % ord(c), ... 0x30 0x31 0x32 0x33 0x34 py> See <http://docs.python.org/lib/built-in-funcs.html#l2h-55> for the ord() function and <http://docs.python.org/lib/typesseq-strings.html> for the "%#x" format -- Gabriel Genellina Great! It works. Thanks a lot. > Great! It works. There is a builtin function called hex() that does the same, but also shares the same problem as the solution above: >>> hex(10) '0xa' This is probably not "nice" in your printouts, it doesn't allign. with the printf inspired solution you can set the precision like this: >>> a = "12\n34" >>> for c in a: ... print "%#04x" % ord(c), ... 0x31 0x32 0x0a 0x33 0x34 regards troels On 2007-06-05, Troels Thomsen <nej> wrote: > with the printf inspired solution you can set the precision like this: >>>> a = "12\n34" >>>> for c in a: > ... print "%#04x" % ord(c), > ... > 0x31 0x32 0x0a 0x33 0x34 And if you just want to do the conversion w/o printing: >>> a = "12\n34" >>> ' '.join(('%#04x' % ord(c) for c in a)) '0x31 0x32 0x0a 0x33 0x34' >>> ' '.join(('%02x' % ord(c) for c in a)) '31 32 0a 33 34' -- Grant Edwards grante Yow! Vote for ME -- I'm at well-tapered, half-cocked, visi.com ill-conceived and TAX-DEFERRED!