> Say, I want to get all files in one folder. Since Dir.entries will
> have "." and ".." included. I want to strip them out with "grep". I
> tried to write in such a way as I can did similarly in Perl:
> log_files = Dir.entries(log_dir).grep(!/^\.\.?/)
> But, it is a syntax error to have "!/regex/" as grep's argument.
> Should I use some trick to make grep accept "not-match" regex?