Ruby Programming Language :: Regexp to extract number with hyphen


	Regexp to extract number with hyphen I have a text with "foo 01-02" in a string. I want to extract foo 01-02 using regexp. reg = /foo (\d+)/ only extracts foo with numbers when there is no hyphen. reg = /foo (\d{1,})\|(\-)\|(\d{1,})/ only extracts foo 01. TIA. bcpar@gmail.com wrote: > I have a text with "foo 01-02" in a string. I want to extract foo > 01-02 using regexp. reg = /foo (\d+)/ only extracts foo with numbers > when there is no hyphen. > reg = /foo (\d{1,})\|(\-)\|(\d{1,})/ only extracts foo 01. TIA. Does this work? /foo (\d+-\d+)/ -- RMagick OS X Installer [http://rubyforge.org/projects/rmagick/] RMagick Hints & Tips [http://rubyforge.org/forum/forum.php?forum_id=1618] RMagick Installation FAQ [http://rmagick.rubyforge.org/install-faq.html] On 5/29/07, bcpar@gmail.com <bcpar@gmail.com> wrote: > I have a text with "foo 01-02" in a string. I want to extract foo > 01-02 using regexp. reg = /foo (\d+)/ only extracts foo with numbers > when there is no hyphen. > reg = /foo (\d{1,})\|(\-)\|(\d{1,})/ only extracts foo 01. TIA. "foo 01-02" =~ /(\d+)-(\d+)/ puts $1 #=> "01" puts $2 #=> "02" The regexp: /foo\ (\d+)\-?(\d)/ seems to work. Still testing... On May 29, 3:57 pm, "Tim Pease" <tim.pe@gmail.com> wrote: - Hide quoted text - > On 5/29/07, bcpar@gmail.com <bcpar@gmail.com> wrote: > > I have a text with "foo 01-02" in a string. I want to extract foo > > 01-02 using regexp. reg = /foo (\d+)/ only extracts foo with numbers > > when there is no hyphen. > > reg = /foo (\d{1,})\|(\-)\|(\d{1,})/ only extracts foo 01. TIA. > "foo 01-02" =~ /(\d+)-(\d+)/ > puts $1 #=> "01" > puts $2 #=> "02" On Wed, May 30, 2007 at 08:15:05AM +0900, bcpar@gmail.com wrote: > The regexp: /foo\ (\d+)\-?(\d)/ > seems to work. Still testing... What exactly are the allowed matches? Only num1-num2, or is num1 by itself allowed? What about num1-num2-num3? /foo ([0-9-]+)/ matches .....foo 1-2-3.... and foo 1-2 and foo 1 /foo (\d+-\d+)/ matches .....foo 1-2.... only /foo (\d+(-\d+)?)/ matches .....foo 1-2.... and foo 1, but not foo-1-2-3 On Tue, 29 May 2007 15:45:34 -0700, bcpar@gmail.com wrote: > I have a text with "foo 01-02" in a string. I want to extract foo 01-02 > using regexp. reg = /foo (\d+)/ only extracts foo with numbers when > there is no hyphen. > reg = /foo (\d{1,})\|(\-)\|(\d{1,})/ only extracts foo 01. TIA. That's because the \| operator in a regexp means either-or. So you're matching foo (\d{1,}) or you're matching (\-) or you're matching (\d{1,}) but not all three at the same time. Others have suggested the following correction: /(\d+)-?(\d+)/ --Ken -- Ken Bloom. PhD candidate. Linguistic Cognition Laboratory. Department of Computer Science. Illinois Institute of Technology. http://www.iit.edu/~kbloom1/ On Wed, May 30, 2007 at 10:40:09PM +0900, Ken Bloom wrote: > Others have suggested the following correction: > /(\d+)-?(\d+)/ That particular example matches 11, but not 1. The most important thing is to be clear about exactly what you want to allow to match or not match; then writing the regexp is easy.